(X^+3x)^2=14(x^2+3x)-40

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Solution for (X^+3x)^2=14(x^2+3x)-40 equation: 



(X^+3X)^2=14(X^2+3X)-40

We move all terms to the left:

(X^+3X)^2-(14(X^2+3X)-40)=0



We calculate terms in parentheses: -(14(X^2+3X)-40), so:

14(X^2+3X)-40

We multiply parentheses

14X^2+42X-40

Back to the equation:

-(14X^2+42X-40)



We get rid of parentheses

-14X^2+(X^+3X)^2-42X+40=0

We add all the numbers together, and all the variables

-14X^2-42X+(X^+3X)^2+40=0

We move all terms containing X to the left, all other terms to the right

-14X^2-42X+(X^+3X)^2=-40

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